java version "1.4.0-beta3"
Java(TM) 2 Runtime Environment, Standard Edition (build 1.4.0-beta3-b84)
Java HotSpot(TM) Client VM (build 1.4.0-beta3-b84, mixed mode)

java.until.zip.ZipFile or ZipInputStream can't unzip file(unicode name) in zip
by winzip8.0

source code:
import java.util.zip.*;
import java.io.*;
public class UnzipF {
    
   private String filename;
    
   public UnzipF(String filename){
      this.filename = filename;
   }
    
   public boolean unzip(){
      try {
         String topdir = filename.substring(0,filename.indexOf(".zip"));
         if (!(new java.io.File(topdir)).mkdir()) System.out.println("topdir of
filename can't created!");
          
         ZipInputStream in = new ZipInputStream(new FileReader(filename));
         //ZipInputStream in = new ZipInputStream(new DataInputStream(new
java.io.FileInputStream(filename)));
         ZipEntry entry;
         String entryname;
         byte[] buf = new byte[4096];
         int len,length;
         String outFilename;
         OutputStream out;
         String dirname;
         while ((entry = in.getNextEntry()) != null) {
            entryname = entry.getName();
            if (!entry.isDirectory()){
               int index = entryname.lastIndexOf('/');
               if(index != -1){
                  dirname = entryname.substring(0,index+1);
                  if (!(new java.io.File(topdir+'/'+dirname)).exists()) (new
java.io.File(topdir+'/'+dirname)).mkdirs() ;
               }
               outFilename = topdir + '/' + entryname;
               out = new java.io.FileOutputStream(outFilename);
               length = 0 ;
               while ((len = in.read(buf)) > 0) {
                  out.write(buf, 0, len);
                  length=length+len;
               }
               out.close();
               System.out.print("outFilename:"+outFilename);
               System.out.println("  length:"+length);
               //System.in.read();
            }
            else {
               if (!(new java.io.File(topdir+'/'+entryname)).exists()) (new
java.io.File(topdir+'/'+entryname)).mkdirs() ;
               System.out.println("topdir+'/'+entryname:"+topdir+'/'+entryname);
            }
         }
         in.close();
         return true;
      } catch (IOException e) {
      	System.out.println("test");
      	System.out.println(e.getMessage());
        return false;
      }
   }
   public static void main(String args[]) {
     UnzipF uf = new UnzipF(args[0]);
     uf.unzip();
   }
}

readme.zip's entry(zip by winzip8.0):
复件 readme.txt
readme.txt


commad:java UnzipF readme.zip

Exception:
Exception in thread "main" java.lang.IllegalArgumentException
        at java.util.zip.ZipInputStream.getUTF8String(ZipInputStream.java:291)
        at java.util.zip.ZipInputStream.readLOC(ZipInputStream.java:230)
        at java.util.zip.ZipInputStream.getNextEntry(ZipInputStream.java:75)
        at UnzipF.unzip(UnzipF.java:24)
        at UnzipF.main(UnzipF.java:58)
(Review ID: 135772) 
======================================================================
Posted Date : 2006-04-11 19:52:31.0

N/A

First four character's-Ansi-numbers from one of the file in readme.zip are
184, 180, 188 and 254. When getUTF8String function from ZipInputStream.java
is invoked during execution, these characters fall under default case (for
above characters case:11 and case:15) in the switch block. The default case is:
default:
                // 10xxxxxx, 1111xxxx
                throw new IllegalArgumentException();
Hence, message 'Exception in thread "main" java.lang.IllegalArgumentException'
gets generated.
So, the question remains is: Do we need to remove case:11 and case:15 from the
default case ?
I removed the case:11 and case:15 from default case and put them in the first 
case in switch statement as: case:0 case:1 case:2 case:3 case:4 case:5 case:6
case:7 case:11 case:15.
The testcase runs fine without any errors/exceptions and unzips the readme.zip
 to generate two files.
  xxxxx@xxxxx   2002-07-09


The above evaluation is incorrect. The real issue is that non-jar zip files usually use encodings other than UTF-8 to encode file names within zip files. This bug is really a duplicate of 4244499.
  xxxxx@xxxxx   2005-1-29 00:22:42 GMT
To use the newly added constructor with a charset 
        ZipInputStream in = new ZipInputStream(new FileInputStream(filename), Charset.forName("ibm437"));
Posted Date : 2009-04-16 22:16:11.0

Fix it as soon as possible please!

fix it, please!!

FIX THIS !!!! It's something we need!

Fix it!!
This is very important!!

Kim

please fix it.

Please fix it soon!

More than a year to fix a bug. This is unacceptable. It 
reminds me of Microsoft's way of handling software bugs.

fix it please~

FIX THIS !!!! It's something we need!

we need this to carry on using java !!

fix this problem asap...thank you guys

fix it plz.. i'm very suprise that you does'nt support this 
thing!!! 

fix it please !!

please fix it !!

it breaks most ZIP files with unicode file names !!!

please fix it!!

We need this man. 

We need this man, please fix it.

we need to rewrite our entire product to use a third party zip class because of this problem ... please fix this.

Is this bug expected to be fixed in near future? If so, when, and in which JDK release?