FULL PRODUCT VERSION :
JDK 1.6_18

ADDITIONAL OS VERSION INFORMATION :
Windows 7

A DESCRIPTION OF THE PROBLEM :
int i=Integer.parseInt(Integer.toBinaryString(-1), 2);
ought to return -1, but


Exception in thread "main" java.lang.NumberFormatException: For input string: "11111111111111111111111111111111" at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
	at java.lang.Integer.parseInt(Integer.java:461)

STEPS TO FOLLOW TO REPRODUCE THE PROBLEM :
Problem occurs every time you try to parse a string with the sign-bit set

Byte.parseByte("11111111",2) fails because it calls Integer.ParseInt and therafter chechs the value againt -128 and -127


REPRODUCIBILITY :
This bug can be reproduced always.

---------- BEGIN SOURCE ----------
	public static void main(String[] args) {
		int num=-1;
		String binString=Integer.toBinaryString(num);
		System.out.println(binString);
		//result: 11111111111111111111111111111111 (32 bits)
		// now try to reverse
		num=Integer.parseInt(binString, 2);
		//and we crashes
		// java.lang.NumberFormatException:
		//For input string: "11111111111111111111111111111111"
	}
---------- END SOURCE ----------

CUSTOMER SUBMITTED WORKAROUND :
		if (binString.charAt(0)=='1')
			binString=binString.substring(1);
		num=Integer.parseInt(binString, 2)-Integer.MIN_VALUE;